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3 weeks ago

The **tension force** of the cable on the elevator is **4000N**.

From the question,

Mass of an elevator(m) = 500kg

It is accelerating **downhill** at a rate of [tex]2\frac{m}{s^{2} }[/tex]. It is necessary to determine the tension force of the cable on the elevator. We know that the **net force** on the elevator when it is traveling downhill is provided by:

**F = m(g - a)**

Here, g is the acceleration due to gravity

g = [tex]9.8\frac{m}{s^{2} }[/tex]

g ≅ 10[tex]\frac{m}{s^{2} }[/tex]

F = 500 × (10 - 2)

F = 500 × 8

F = **4000N**

Therefore, the **tension force** of the cable on the elevator is **4000N**.

Learn more about **Acceleration** here:

https://brainly.com/question/460763

Question

4. A 20-kg box sits on an incline of 30° from the horizontal. The coefficient of friction between the box and the incline is o.30. Find the acceleration of the box down the incline.

Solution 1

The box** accelerates** down the incline at 2.4m/s^2.

A mass m particle will slide down a smooth inclined plane if it is released onto it with a** friction force** F=0. We resolve in the direction of motion to determine the particle's **acceleration **as it slides. F = ma, mg cos(90) = ma, gg cos(90) = a, gg sin() = a.

By using zigmaFx = max, we will determine the acceleration.

However, we must first determine the friction force Ff.

Because cos 30 degree = 0.866 and Fy = ma y = 0 result in FN - 0.87mg = 0, we may calculate FN as (0.87)(20Kg)(9.81 m/s2) = 171N.

From Ff = mue FN = 0.30)(171 N)= 51N, we can now calculate Ff.

We get Ff - 0.50mg = ma x 51N - (0.50)(20)(9.81)N = (20kg)(ax) from the expression zigmaFx = max, where ax = -2.35 m/s2.

At 2.4 m/s2, the box quickens its descent of the hill.

To learn more about **acceleration** refer to:

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Question

You are a crash test analyst for Toyota. Car 1 (mass = 900 kg) is at rest while Car 2 (mass = 1700 kg) is traveling toward Car 1 at 15.0 m/s. The two cars collide and and their bumpers stick together. What is the resulting momentum after the collision?

Solution 1

The **momentum **after the collision is 25500 kg⋅m/s. Each object's momentum may change, but the overall momentum must not change.

In Newtonian mechanics, **momentum **is calculated as the sum of an object's mass and velocity. It has a magnitude and a direction, making it a vector quantity.

The rate of change of a body's momentum is equal to the net force exerted on it, according to Newton's second** law of motion**. Regardless of the frame of reference, momentum is a conserved quantity in any inertial frame, which means that if an enclosed system is not subject to outside influences, its total linear momentum remains constant.

The formula for calculating momentum is expressed as

momentum = mass x velocity

According to the law of conservation of momentum, initial momentum = final momentum

The formula for initial momentum is

m1u1 + m2u2

where

m1 = mass of first car

u1 = initial velocity of first car

m2 = mass of second car

u2 = initial velocity of second car

From the information given,

m1 = 900

u1 = 0 because it is at rest

m2 = 1700

u2 = 15.0 m/s

Initial momentum = 900 x 0 + 1700 x 15.0 = 25500

Momentum after the collision is 25500 kg⋅m/s

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Question

which type of which type of orbit is shown in the picture below?

Solution 1

**I don't see a picture attached to your question. Without one, I don't think I will be able to determine what type of orbit is displayed.**

Question

On a train moving , 75 m/s you roll a ball towards the front of the train with a speed of 5m/s. Your friend standing some unknown distance away from you catches it. To a person outside the train, the ball traveled 220m until it was caught. How far away is your friend standing from you?

Solution 1

The **distance** of your friend from you is 15.7 m.

The **time** take for the **ball** to travel to you friend is calculated by applying the principle of relative velocity as shown below.

( Vt - Vb ) t = d

where;

- Vt is the velocity of the train
- Vb is the velocity of the ball
- t is the time of motion of the ball
- d is the distance travelled by the ball

( Vt - Vb ) t = d

(75 - 5) t = 220

70t = 220

t = 220 / 70

t = 3.14 s

The **distance** of your friend from you is calculated as;

d1 = 5 m/s x 3.14 s

d1 = 15.7 m

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Question

A star was observed to have a planet orbiting it at a distance of 1.12×108 km. The orbital period of the planet is 329 days. Calculate the mass of the star.

Solution 1

The **mass** of the star would be **9.97 x 10³⁵ Kg**.

- Stars are huge
**celestial bodies**made mostly of**hydrogen**and**helium**that produce light and heat from the churning**nuclear forges**inside their cores. - We can write the relation
**absolute magnitude****[M]**and**apparent magnitude [m]**as follows :**M = m + 5(log₁₀p + 1).** - The
**centripetal force**is the force needed to make a body move in circular motion. It is given by :**F{C} = mv²/r**

We have a star was observed to have a planet orbiting it at a distance of **1.12 × 10⁸ km**. The orbital period of the planet is **329 days.**

Let the mass of **star** be** [M]** and that of **planet** be** [m]**. Since, the planet **revolves** around the star, we can write -

**F{Centripetal} = F{Gravitation}**

**mv²/r = GMm/r²**

v² = GM/r

(rω)² = GM/r

r²ω² = GM/r

ω² = GM/r³

(2π/T)² = GM/r³

M = (2π/T)² (r³)/G

M = 46.8 x (r³)/G

M = {46.8 x (1.12)³ x (10⁸)³}/{(6.6) x 10 ⁻¹¹}

M = (65.7/6.6) x (10²⁴/ 10 ⁻¹¹)

**M = 9.97 x 10³⁵ Kg**

Therefore, the **mass** of the star would be **9.97 x 10³⁵ Kg**.

To solve more questions on** Stars and astronomy**, visit the link below-

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Question

how was the third law of motion discovered

Solution 1

**Answer:**

how was the third law of motion discovered

**Explanation:**

Isaac Newton discovered this law by exerting pressure on one object against another. The first object's force is felt and equally replicated by the second body. Thus, Isaac Newton proved that it's impossible to exert pressure on a single object without a similar reaction from the second object.

Solution 2

Answer and Explanation:

Isaac Newton discovered this law by exerting pressure on one object against another. The first object's force is felt and equally replicated by the second body. Thus, Isaac Newton proved that it's impossible to exert pressure on a single object without a similar reaction from the second object.

Isaac Newton discovered this law by exerting pressure on one object against another. The first object's force is felt and equally replicated by the second body. Thus, Isaac Newton proved that it's impossible to exert pressure on a single object without a similar reaction from the second object.

Question

Which statement best describes the relationship between changes in air pressure and wind speeds?

Responses

When a high- and a low-pressure air mass are far apart, air moves quickly from high to low pressure.

When a high- and a low-pressure air mass are far apart, air moves slowly from high to low pressure.

When a high- and a low-pressure air mass are close together, air moves slowly from high to low pressure.

When a high- and a low-pressure air mass are far apart, air moves quickly from low to high pressure.

Responses

When a high- and a low-pressure air mass are far apart, air moves quickly from high to low pressure.

When a high- and a low-pressure air mass are far apart, air moves slowly from high to low pressure.

When a high- and a low-pressure air mass are close together, air moves slowly from high to low pressure.

When a high- and a low-pressure air mass are far apart, air moves quickly from low to high pressure.

Solution 1

The best statement that best describes the relationship between changes in **air pressure **and **wind speeds** is when a **high**- and a** low-pressure** **air mass** are far apart, air moves quickly from high to low pressure.

The greater the increase or decrease in **pressure**, the faster the **winds move**. When a **high**- and a **low-pressure air mass **are far apart, air moves slowly from high to low pressure. When a high- and a low-pressure air mass are close, the air moves slowly from a point of high to low pressure. When a high- and a low-pressure air are far apart, the air moves rapidly from a region of high pressure to a region of low pressure.

Learn more about **winds**:https://brainly.com/question/28040719

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Question

Can someone please help meeeeeeee! I’m so bad at these stuff. Ill give brainliest too

Solution 1

1.) The Northern Hemisphere refers to the half of the planet that is north of the equator, while the Southern Hemisphere is all of the planet south of the equator.

2.) the rate of decrease is larger the higher the latitude.

3.) 9 hours, 46 minutes

4.) Key West, FL 78.1°F

5.) Russian city of Yakutsk

Last one don’t know how to answer sorry

2.) the rate of decrease is larger the higher the latitude.

3.) 9 hours, 46 minutes

4.) Key West, FL 78.1°F

5.) Russian city of Yakutsk

Last one don’t know how to answer sorry

Question

an object with a mass of 13.29 kg experiences force of 14.35 N . What is the acceleration of the object?

Solution 1

**(Note): Acceleration = Force * Mass**

**____________________________________________________**

We are given the following:

- [tex]Mass=13.29kg[/tex]
- [tex]Force=14.35N[/tex]
- [tex]Question:[/tex]
*What is the acceleration of the object?*

Given the formula for finding **acceleration, **we fill in the blanks.

[tex]A=14.35*13.29[/tex]

[tex]A=190.7115=190.7[/tex] ← **Acceleration/Final Solution**

**_____________________________________________________**

**Hope this helps!**

Question

Strength training is beneficial because it decreases your risk of injury. Which statement BEST describes why this is true? A. Muscular fitness training can prevent or improve diabetes and sarcopenia. B. Muscular fitness training increases muscle mass, which increases your metabolism. C. Muscular fitness training strengthens tendons, ligaments, and cartilage. D. Muscular fitness training improves self-image and athletic performance. Please select the best answer from the choices provided. A B C D

Solution 1

Answer: B. Muscular fitness training increases muscle mass, which increases your metabolism

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