A 500 kg empty elevator moves with a downwards acceleration of 2 m/s2. What is the tension force of the cable on the elevator?

3 weeks ago

Solution 1

Guest Guest #7253026
3 weeks ago

The tension force of the cable on the elevator is 4000N.

From the question,

Mass of an elevator(m) = 500kg

It is accelerating downhill at a rate of [tex]2\frac{m}{s^{2} }[/tex]. It is necessary to determine the tension force of the cable on the elevator. We know that the net force on the elevator when it is traveling downhill is provided by:

F = m(g - a)

Here, g is the acceleration due to gravity

g = [tex]9.8\frac{m}{s^{2} }[/tex]

g ≅ 10[tex]\frac{m}{s^{2} }[/tex]

F = 500 × (10 - 2)

F = 500 × 8

F = 4000N

Therefore, the tension force of the cable on the elevator is 4000N.

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The box accelerates down the incline at 2.4m/s^2.

How do you find the acceleration of an incline box?

A mass m particle will slide down a smooth inclined plane if it is released onto it with a friction force F=0. We resolve in the direction of motion to determine the particle's acceleration as it slides. F = ma, mg cos(90) = ma, gg cos(90) = a, gg sin() = a.

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The momentum after the collision is 25500 kg⋅m/s. Each object's momentum may change, but the overall momentum must not change.

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In Newtonian mechanics, momentum is calculated as the sum of an object's mass and velocity. It has a magnitude and a direction, making it a vector quantity.

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The time take for the ball to travel to you friend is calculated by applying the principle of relative velocity as shown below.

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We are given the following:

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