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# A 500 kg empty elevator moves with a downwards acceleration of 2 m/s2. What is the tension force of the cable on the elevator?

3 weeks ago

## Solution 1

Guest #7253026
3 weeks ago

The tension force of the cable on the elevator is 4000N.

From the question,

Mass of an elevator(m) = 500kg

It is accelerating downhill at a rate of $$2\frac{m}{s^{2} }$$. It is necessary to determine the tension force of the cable on the elevator. We know that the net force on the elevator when it is traveling downhill is provided by:

F = m(g - a)

Here, g is the acceleration due to gravity

g = $$9.8\frac{m}{s^{2} }$$

g ≅ 10$$\frac{m}{s^{2} }$$

F = 500 × (10 - 2)

F = 500 × 8

F = 4000N

Therefore, the tension force of the cable on the elevator is 4000N.

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4. A 20-kg box sits on an incline of 30° from the horizontal. The coefficient of friction between the box and the incline is o.30. Find the acceleration of the box down the incline.
Solution 1

The box accelerates down the incline at 2.4m/s^2.

### How do you find the acceleration of an incline box?

A mass m particle will slide down a smooth inclined plane if it is released onto it with a friction force F=0. We resolve in the direction of motion to determine the particle's acceleration as it slides. F = ma, mg cos(90) = ma, gg cos(90) = a, gg sin() = a.

By using zigmaFx = max, we will determine the acceleration.

However, we must first determine the friction force Ff.

Because cos 30 degree = 0.866 and Fy = ma y = 0 result in FN - 0.87mg = 0, we may calculate FN as (0.87)(20Kg)(9.81 m/s2) = 171N.

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At 2.4 m/s2, the box quickens its descent of the hill.

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You are a crash test analyst for Toyota. Car 1 (mass = 900 kg) is at rest while Car 2 (mass = 1700 kg) is traveling toward Car 1 at 15.0 m/s. The two cars collide and and their bumpers stick together. What is the resulting momentum after the collision?
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The momentum after the collision is 25500 kg⋅m/s. Each object's momentum may change, but the overall momentum must not change.

### What is Momentum ?

In Newtonian mechanics, momentum is calculated as the sum of an object's mass and velocity. It has a magnitude and a direction, making it a vector quantity.

The rate of change of a body's momentum is equal to the net force exerted on it, according to Newton's second law of motion. Regardless of the frame of reference, momentum is a conserved quantity in any inertial frame, which means that if an enclosed system is not subject to outside influences, its total linear momentum remains constant.

The formula for calculating momentum is expressed as

momentum = mass x velocity

According to the law of conservation of momentum, initial momentum = final momentum

The formula for initial momentum is

m1u1 + m2u2

where

m1 = mass of first car

u1 = initial velocity of first car

m2 = mass of second car

u2 = initial velocity of second car

From the information given,

m1 = 900

u1 = 0 because it is at rest

m2 =  1700

u2 = 15.0 m/s

Initial momentum = 900 x 0 +  1700 x 15.0 = 25500

Momentum after the collision is 25500 kg⋅m/s

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I don't see a picture attached to your question. Without one, I don't think I will be able to determine what type of orbit is displayed.

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On a train moving , 75 m/s you roll a ball towards the front of the train with a speed of 5m/s. Your friend standing some unknown distance away from you catches it. To a person outside the train, the ball traveled 220m until it was caught. How far away is your friend standing from you?​
Solution 1

The distance of your friend from you is 15.7 m.

### What is the time of motion of ball?

The time take for the ball to travel to you friend is calculated by applying the principle of relative velocity as shown below.

( Vt - Vb ) t = d

where;

• Vt is the velocity of the train
• Vb is the velocity of the ball
• t is the time of motion of the ball
• d is the distance travelled by the ball

( Vt - Vb ) t = d

(75 - 5) t = 220

70t = 220

t = 220 / 70

t = 3.14 s

The distance of your friend from you is calculated as;

d1 = 5 m/s x 3.14 s

d1 = 15.7 m

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A star was observed to have a planet orbiting it at a distance of 1.12×108 km. The orbital period of the planet is 329 days. Calculate the mass of the star.
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The mass of the star would be 9.97 x 10³⁵ Kg.

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• Stars are huge celestial bodies made mostly of hydrogen and helium that produce light and heat from the churning nuclear forges inside their cores.
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We have a star was observed to have a planet orbiting it at a distance of 1.12 × 10⁸ km. The orbital period of the planet is 329 days.

Let the mass of star be [M] and that of planet be [m]. Since, the planet revolves around the star, we can write -

F{Centripetal} = F{Gravitation}

mv²/r = GMm/r²

v² = GM/r

(rω)² = GM/r

r²ω² = GM/r

ω² = GM/r³

(2π/T)² = GM/r³

M = (2π/T)² (r³)/G

M = 46.8 x (r³)/G

M = {46.8 x (1.12)³ x (10⁸)³}/{(6.6) x 10 ⁻¹¹}

M = (65.7/6.6) x (10²⁴/ 10 ⁻¹¹)

M = 9.97 x 10³⁵ Kg

Therefore, the mass of the star would be 9.97 x 10³⁵ Kg.

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how was the third law of motion discovered
Solution 1

Answer:

how was the third law of motion discovered

Explanation:

Isaac Newton discovered this law by exerting pressure on one object against another. The first object's force is felt and equally replicated by the second body. Thus, Isaac Newton proved that it's impossible to exert pressure on a single object without a similar reaction from the second object.

Solution 2
Answer and Explanation:
Isaac Newton discovered this law by exerting pressure on one object against another. The first object's force is felt and equally replicated by the second body. Thus, Isaac Newton proved that it's impossible to exert pressure on a single object without a similar reaction from the second object.
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Responses

When a high- and a low-pressure air mass are far apart, air moves quickly from high to low pressure.

When a high- and a low-pressure air mass are far apart, air moves slowly from high to low pressure.

When a high- and a low-pressure air mass are close together, air moves slowly from high to low pressure.

When a high- and a low-pressure air mass are far apart, air moves quickly from low to high pressure.
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The best statement that best describes the relationship between changes in air pressure and wind speeds is when a high- and a low-pressure air mass are far apart, air moves quickly from high to low pressure.

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1.) The Northern Hemisphere refers to the half of the planet that is north of the equator, while the Southern Hemisphere is all of the planet south of the equator.
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Solution 1
• (Note): Acceleration = Force * Mass

____________________________________________________

We are given the following:

1. $$Mass=13.29kg$$
2. $$Force=14.35N$$
3. $$Question:$$ What is the acceleration of the object?

Given the formula for finding acceleration, we fill in the blanks.

$$A=14.35*13.29$$

$$A=190.7115=190.7$$ ← Acceleration/Final Solution

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